CS605 Current Midterm Paper Fall 2013 shared by Dazzling Bobby File 7

on December 28, 2013 at 10:00pm

MCQs

1.     1. Which is not object oriented life cycle model? ANS: Remember name of object oriented models

2.     2. First published model of software development process was……… Answer: waterfall

3.     3. Qualitative feedback of CMM is………………. ANS: Optimizing

4.     4. ………………. are those that the user has the option of using one or none of the subgroups during an elementary process. Answer: Optional subgroups

5.     5. In functional point EQ stands for……………….. Answer: External inquiry

6.     6. UNPL stands for……………………. Answer: Upper Natural Process Limit

7.     7. TSS stands for………………… answer: Task Set Selector

8.     8. ……………….is the ability to encourage technical people to produce to their best.

Answer: Motivation

9.     Line of code heavily dependent on……… Answer: individual programming style  page 37

10.  Evolutionary model………………..

11.  A process model defines a task set which comprises of SE work tasks ………… and deliverables. Answer: milestones

12.  Which is not included in software development loop? Answer: Remember name on Page 11

13.  ………. structures a team along a traditional hierarchy of authority Answer: Closed paradigm

14.  Every task or group of tasks should be associated with a project ………. Answer: milestones

Subjective:

1.     Difference between optional and mandatory.                        2marks

2.     Every task or group of tasks should be associated with a project milestone. Explain benefit? 2marks

3.     Buy vs build. 3marks

4.     Benefit of control chart?         3marks

5.     Ex of page 89?                        5marks

Solution:

Risk:

·       Only 70% of the software components scheduled for reuse will, in fact, be integrated into the application. The remaining functionality will have to be custom developed.

·       Risk Probability – 80% likely (i.e. 0.8)

Risk impact

·       60 reusable software components were planned. If only 70% can be used, 18 components would have to be developed from scratch. Since the average component will cost 100,000, the total cost will be 1,800,000.

• Therefore, RE = 0.8 * 1,800,000 = 1,440,000

6.     HRM was given. We have to tell only which information is optional and mandatory.          5marks